Bhabha University - private university in Bhopal, Madhya Pradesh, India. Article “Bhabha University” in English Wikipedia has 22.4 points for quality (as of July 1, 2025). The article contains 4 references and 1 sections.
Since the creation of article “Bhabha University”, its content was written by 14 registered users of English Wikipedia and edited by 14 registered Wikipedia users in all languages.
The article is cited 66 times in English Wikipedia and cited 66 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | English: #851358 07.2021 |
Global: #1434465 07.2021 |
| Best Rank | English: #22365 07.2021 |
Global: #96159 07.2021 |
On 28 February 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: Ali Khamenei, Iran, Ruhollah Khomeini, Jeffrey Epstein, Supreme Leader of Iran, Mohammad Reza I of Iran, 2026 Israeli–United States strikes on Iran, Neil Sedaka, Masoud Pezeshkian, Resident Evil Requiem.
In English Wikipedia the most popular articles on that day were: Ali Khamenei, 2026 Israeli–United States strikes on Iran, Neil Sedaka, Iran, Ruhollah Khomeini, Iran–Israel conflict, Supreme Leader of Iran, Scream 7, Elimination Chamber (2026), World War III.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(4.01+3.25+14.29+7.14+83.41)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
